108t-6t^2=0

Solution for 108t-6t^2=0 equation:

108t-6t^2=0

a = -6; b = 108; c = 0;
Δ = b2-4ac
Δ = 1082-4·(-6)·0
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(108)-108}{2*-6}=\frac{-216}{-12}
=+18
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(108)+108}{2*-6}=\frac{0}{-12}
=0
$